Are you smart enough to be an astronaut?

[vienna]

Originally Posted by Dowly

D was my other candidate before I noticed B lines up diagonally as well. Another thing I noticed just now about B is that all the corners of the center piece supplement the shape and colors it touches outside of it.


i.e. if you put B in the center, the top left shape is black triangle. To the left of it is a light grey triangle, diagonally there's a white triangle and upwards there's a grey triangle. All four colors are touching. This is the same for the other corners of the center B.


So that's four things going for it being B. I think I'm ready to place my bet.

That was basically the same reasoning I used for my answer; I was looking for a symmetry of pattern in the puzzle and the only one I could immediately see was, if "B" was inserted into the center, there was a grouping of the four shapes, all with the same pattern of shadings, in the same order.; I didn't even consider diagonal relationships...


As far as taking my reasoning to my grave, well, hyperbole...


...and I also have no desire to be an astronaut; I have enough difficulty getting across town on the bus...




<O>

[mapuc]

I can tell you that it demands a lot and I mean a lot more than getting these IQ test correct to become an astronaut.

Markus

[August]

Originally Posted by Catfish

While i posted it should be 'b', there would be another possibility.

Making the case for 'd' it is the only one that has nothing in common with all others, which is also a solution in itself

Yeah but D doesn't match the color pattern. All other squares have the same colors in each location, only the shapes change.

[Platapus]

Originally Posted by August

B. The grid pattern is that the colors stay in the same places but all four shapes have to be different than the grids on either side. Only choice B meets both of those requirements, vertically, horizontally and diagonally.

Winner!


"the pattern mirrors adjacent shapes but in different colors."

[Platapus]

Number 2

[August]

Originally Posted by Platapus

Winner!


"the pattern mirrors adjacent shapes but in different colors."

You saying I ain't eloquent enough to be an Astronut?

[August]

Originally Posted by Platapus

Number 2

The three wheels in the middle seem to be a combination of larger, smaller and the same size as 1 & 2 so my guess would be A. As fast as wheel 1.

[Platapus]

Another wiener!!!


"wheels of same radius at start and end of the sequence will spin at the same speed."

[Platapus]

Last one

[3catcircus]

Originally Posted by August

The three wheels in the middle seem to be a combination of larger, smaller and the same size as 1 & 2 so my guess would be A. As fast as wheel 1.

Visually and logically, same size wheels should rotate at the same speed when one is the driver and the other is driven by it. What complicates things is not knowing the sizes of the idler wheels, so you have to assume they will result in cancelling each other out or fool yourself into believing that they're going to have different angular speeds - unless you can do the math to prove it to yourself.

Easiest thing to do is to apply the law of gearing and assume each wheel is a gear with a single tooth, and then do the calcs for a compound gear train. Your result should match your gut instinct that both wheels that are the same size will spin at the same speed. But again - to do this you'll need to know the diameters of all the wheels.

[August]

Originally Posted by Platapus

Last one

I'm thinking it's B, the cylinder. An imaginary line running down the center axis would be equidistant from all surfaces. All the other choices would eventually run into a surface.

Originally Posted by 3catcircus

Visually and logically, same size wheels should rotate at the same speed when one is the driver and the other is driven by it. What complicates things is not knowing the sizes of the idler wheels, so you have to assume they will result in cancelling each other out or fool yourself into believing that they're going to have different angular speeds - unless you can do the math to prove it to yourself.

Easiest thing to do is to apply the law of gearing and assume each wheel is a gear with a single tooth, and then do the calcs for a compound gear train. Your result should match your gut instinct that both wheels that are the same size will spin at the same speed. But again - to do this you'll need to know the diameters of all the wheels.

I figure that since they didn't specify then it was a safe assumption.

[3catcircus]

Originally Posted by Platapus

Last one

I'm thinking it's the sphere. All points on the surface aimed towards and passing through the middle (i.e. center) will be equidistant since there is only one surface (well, a coplanar inner and outer surface joined by umbilics).

[mapuc]

Totally wrong comment in an interesting thread

Markus

[Platapus]

And a third winner!


I only got two our of three and one of those I got I just remembered from another article.

[d@rk51d3]

Originally Posted by August

You saying I ain't eloquent enough to be an Astronut?

Maybe have to settle for “space cadet”.