John P. Cromwell attack technique on order

XLjedi · 10-22-08, 09:10 PM

Sorry... I cut the 70° in half to 35° I guess I should've cut the 20° in half too.
(and I'm just gonna claim stupidity for saying 35.5° is half of 70°)

Assuming you're on a 45° track to the target TC and you just set AoB as 35° you should be able to get a +-5° solution (close enough to zero) at the 10° bearing. You would set the target speed for whatever the target speed is and let the TDC calc the +-5 track. Just leave distance at ohhh... 1000-1500 or so and you should be fine.

When I suggested a 20° approximation for the 90° approach angle I was assuming you were going to use your TDC to get an exact track solution (but close enough to zero gyro) to hit anything inside of 2000 yds (maybe further).

I haven't tested it, but I would think that a +-5 gyro angle wouldn't introduce enough error to miss inside of 2000yds. It's only the little bit of torpedo advance that skews the solution with regard to distance, and I doubt a few degrees is gonna matter too much if I just set a 1500yd distance and forget about it.

So you're on a 45° track and target is moving at 12kts.

Try setting aiming wire at 10° and AoB 35°, speed 12 and MARK (hit input button). That should give a solution close to zero gyro. Now fire as points of interest pass the wire on the 10° mark.

I was just looking for ways to simplify the TDC data entry and allow the TDC to solve for the angle... similar to Fast-90. Notice the only variable above is speed, I don't need to keep a lookup table of degrees for zero gyro shots.

But it's up to you all if you want to do the math, if you like super precision and hitting targets at 8000 yards that's fine too.

10 and 35 seem to work OK for a 46kt torpedo... and what's the other torp speed? ...probably close enough for other speeds too.

10-22-08, 09:10 PM	#11
XLjedi Ace of the Deep Join Date: Jun 2005 Location: Palm Beach, Florida Posts: 1,243 Downloads: 53 Uploads: 8	Sorry... I cut the 70° in half to 35° I guess I should've cut the 20° in half too. (and I'm just gonna claim stupidity for saying 35.5° is half of 70°) Assuming you're on a 45° track to the target TC and you just set AoB as 35° you should be able to get a +-5° solution (close enough to zero) at the 10° bearing. You would set the target speed for whatever the target speed is and let the TDC calc the +-5 track. Just leave distance at ohhh... 1000-1500 or so and you should be fine. When I suggested a 20° approximation for the 90° approach angle I was assuming you were going to use your TDC to get an exact track solution (but close enough to zero gyro) to hit anything inside of 2000 yds (maybe further). I haven't tested it, but I would think that a +-5 gyro angle wouldn't introduce enough error to miss inside of 2000yds. It's only the little bit of torpedo advance that skews the solution with regard to distance, and I doubt a few degrees is gonna matter too much if I just set a 1500yd distance and forget about it. So you're on a 45° track and target is moving at 12kts. Try setting aiming wire at 10° and AoB 35°, speed 12 and MARK (hit input button). That should give a solution close to zero gyro. Now fire as points of interest pass the wire on the 10° mark. I was just looking for ways to simplify the TDC data entry and allow the TDC to solve for the angle... similar to Fast-90. Notice the only variable above is speed, I don't need to keep a lookup table of degrees for zero gyro shots. But it's up to you all if you want to do the math, if you like super precision and hitting targets at 8000 yards that's fine too. 10 and 35 seem to work OK for a 46kt torpedo... and what's the other torp speed? ...probably close enough for other speeds too. __________________ Last edited by XLjedi; 10-22-08 at 09:23 PM.