(Yet another) Attempt to make sense of gyro angles

[makman94]

Originally Posted by Von Due

Just curious. Those tables you show there (I have them too), how were those values found? ....

the tables were created with excel programm,

if you apply the law of sines on the triangle that containes the angle 'x' (look at the image at my previous post) you get :

x = arctan{sin(lb2) / [(u1/u2) + cos(lb2)]} ,where u1=torpedo speed and u2=target speed

and excel gave all the outputs that you see on tables. (i ,then, rounded these outputs to one decimal digit before print them one tables)