intercept target solutions ? geometrical method ?

[Pisces]

Originally Posted by sENoZ

i do this with knowledge ^^

Well me i dont see where you find 38
cause if target speed is 10 and my torpedo is 28 and i shoot at 38 angle ? angle will be way too much. the torpedo will for sure cross the course of the target, but way too late..

I don't know what your language is that might cause misunderstandings, but I thought the language of mathematics and arithmetic was universal across most of the world:

1+2=3

38 is what I get when I apply your rule for shooting angle/lead with the known numbers:

target speed + torpedo speed = 10 + 28 =38

I know it is an incorrect number for shooting, resulting is a missed torpedo. But that is how you explained your rule. And I know you wrote that the uboat needs to be at 90 degrees to the course of the target when you fire. But that does not explain how your odd rule works and results to 20.

by the way you should be able to read that tablet ^^ it is for 30 knots torpedo but maybe you will understand..

Ok, that would be the missing link you left out in your explanation. That table calculates the exact same shooting angle as the TDC based on AOB and target speed. So, if that is what you use then you are using a paper TDC. It's the same mathematics! Not different. Not simpler.