The Bearing Rate Course Finding method

Diopos · 08-26-10, 11:32 AM

Quote:

Originally Posted by Munchausen

Not always. Say the target cuts across your bow at about a 45 degree angle. It will be closest when on (or near) the bow and will be further away when AOB reaches 90.

The minimum distance between a point A and a line is AB, B being the point where a Vertical -passing through A- cuts the line.

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Pisces · 08-26-10, 01:08 PM

Well, you wanted an equal-bearing interval method, so this one is not what you want. It's a slide-rule for the 3-bearing equal time interval method. You can still do the same, but it's just a different variable you are measuring. I'm not sure if you were allready aware of it. I think you do. Oh well,

http://www.subsim.com/radioroom/showthread.php?t=147719

(This is the SH3 thread, I also made one in the SH4 section back then, but it's all the same ofcourse)

The formula for the calculation is explained and proven in this document, around page 4.

http://www.filefront.com/17237360/NO...s_Only_TMA.pdf

It certainly seems to lend itself for a fixed bearing interval approach, but only with a digital calculator I fear. Making a sliderule for it would require another extra scale independant from the 2 that the fixed-time interval requires. The fixed bearing interval would require independant scales for both time periods, as wel as one for the size of the bearing interval (which I expect one would not like that to be built-in value). Or reducing the 2 'time' disks to one 'ratio of times'-disk wouldn't help in practice. You'd still have to do the division manually.

I haven't figured out how to construct such a thing. But after I finished working on the above slide-rule I definately thought about trying to implement it too. However the complexity of the formula got the better of me. Maybe it's time to pick up the attempt again. (it certainly beats wasting braincells on 8010)

Rockin Robbins · 08-26-10, 02:18 PM

Quote:

Originally Posted by Diopos

The minimum distance between a point A and a line is AB, B being the point where a Vertical -passing through A- cuts the line.

.

Minor correction, not a vertical but a perpendicular.

Diopos · 08-26-10, 02:46 PM

Quote:

Originally Posted by Rockin Robbins

Minor correction, not a vertical but a perpendicular.

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08-26-10, 01:08 PM	#2
Pisces Silent Hunter Join Date: Dec 2004 Location: AN9771 Posts: 4,904 Downloads: 304 Uploads: 0	Well, you wanted an equal-bearing interval method, so this one is not what you want. It's a slide-rule for the 3-bearing equal time interval method. You can still do the same, but it's just a different variable you are measuring. I'm not sure if you were allready aware of it. I think you do. Oh well, http://www.subsim.com/radioroom/showthread.php?t=147719 (This is the SH3 thread, I also made one in the SH4 section back then, but it's all the same ofcourse) The formula for the calculation is explained and proven in this document, around page 4. http://www.filefront.com/17237360/NO...s_Only_TMA.pdf It certainly seems to lend itself for a fixed bearing interval approach, but only with a digital calculator I fear. Making a sliderule for it would require another extra scale independant from the 2 that the fixed-time interval requires. The fixed bearing interval would require independant scales for both time periods, as wel as one for the size of the bearing interval (which I expect one would not like that to be built-in value). Or reducing the 2 'time' disks to one 'ratio of times'-disk wouldn't help in practice. You'd still have to do the division manually. I haven't figured out how to construct such a thing. But after I finished working on the above slide-rule I definately thought about trying to implement it too. However the complexity of the formula got the better of me. Maybe it's time to pick up the attempt again. (it certainly beats wasting braincells on 8010) __________________ My site downloads: https://ricojansen.nl/downloads