Quantum leap

[Sailor Steve]

Give it up, Frau Brau. These luddites have no understanding of technology.

[DarkFish]

Originally Posted by Sailor Steve

Give it up, Frau Brau. These luddites have no understanding of technology.

yeah, that's why I'm studying Electrical Engineering
I hope you do understand it will be me and my colleagues who'd develop such a teleporting application?

[Sailor Steve]

Originally Posted by DarkFish

yeah, that's why I'm studying Electrical Engineering
I hope you do understand it will be me and my colleagues who'd develop such a teleporting application?

Of course. I can pretty much guarantee that anybody here understands the technology better than I do. I was just adding to the beer jokes and Frau K's comment on "Magicks".

[frau kaleun]

Originally Posted by DarkFish

yeah, that's why I'm studying Electrical Engineering
I hope you do understand it will be me and my colleagues who'd develop such a teleporting application?

Well, at the very least you'll do most of the wiring and help with the testing. We'll need to beam a few guys in red shirts through the system to make sure all the kinks are worked out before we put anyone's beer at risk.

[DarkFish]

Originally Posted by Sailor Steve

Of course. I can pretty much guarantee that anybody here understands the technology better than I do. I was just adding to the beer jokes and Frau K's comment on "Magicks".

I know, I know

I guess the overly extensive mathematics lessons I get at uni have degenerated my brain to an extent where I can only see things in formulas... No more "Magicks" for me...

But still, if you take a function f(t) for the age of beer, and differentiate it on the interval [0,t], and once more on the interval [-t,0], you'll find that both are first-degree functions, and that f'(t) equals f'(-t) (as f(t) is a continuous function). From this you can conclude that beer traveling backwards in time loses age exactly as fast as beer traveling forward in time gains age.
So:

∀t∈ℝ, ∂f∈ℕ, 0 ≤ ∂f ≤ 2: f'(t)=-f'(-t) ⇒ f'(t)+f'(-t)=0 ⇒ ∫[0,t]f'(t)dt+f(t)+∫[-t,0]f'(t)dt=f(t)

Wherein f(t) is the age of beer and f'(t) is the aging speed.

Q.E.D.


Now try to prove me wrong

[DarkFish]

Originally Posted by frau kaleun

Well, at the very least you'll do most of the wiring and help with the testing. We'll need to beam a few guys in red shirts through the system to make sure all the kinks are worked out before we put anyone's beer at risk.

Sorry, I won't volunteer for that. Suppose it goes wrong and I end up someplace/sometime where they haven't got beer?
That would be horrible

[frau kaleun]

So:

∀t∈ℝ, ∂f∈ℕ, 0 ≤ ∂f ≤ 2: f'(t)=-f'(-t) ⇒ f'(t)+f'(-t)=0 ⇒ ∫[0,t]f'(t)dt+f(t)+∫[-t,0]f'(t)dt=f(t)

Wherein f(t) is the age of beer and f'(t) is the aging speed.

Q.E.D.


Now try to prove me wrong

[TLAM Strike]

Originally Posted by DarkFish

yeah, that's why I'm studying Electrical Engineering
I hope you do understand it will be me and my colleagues who'd develop such a teleporting application?

This is about physics, not engineering. The two are not connected. See... physics makes sense. Stuff done by Engineers as a rule makes no sense.

Originally Posted by Raptor1

The ansible! It works!

...sort of...

and sort of an anagram for Lesbian. Actually not sort of...

Originally Posted by frau kaleun

No because it ages backwards during transmission. Like Merlin. Because of all the quantum magicks, and stuff.

That is only if they are using Tachyons. As far as I know Tachyons have nothing to do with Quantum Entanglement.

[Weiss Pinguin]

Originally Posted by frau kaleun

Well, at the very least you'll do most of the wiring and help with the testing. We'll need to beam a few guys in red shirts through the system to make sure all the kinks are worked out before we put anyone's beer at risk.

What about Admiral Archer's dog?

[Oberon]

Originally Posted by DarkFish

In that case it wouldn't matter a thing. If you'd get tomorrow's beer today, it would be a day younger than today's. But in the time it takes to become tomorrow's beer, it would grow a day older. 1-1=0 so there would be no difference.

[Oberon]

Originally Posted by Weiss Pinguin

What about Admiral Archer's dog?

Dunno...they still haven't found him...

[Oberon]

Originally Posted by DarkFish

So:

∀t∈ℝ, ∂f∈ℕ, 0 ≤ ∂f ≤ 2: f'(t)=-f'(-t) ⇒ f'(t)+f'(-t)=0 ⇒ ∫[0,t]f'(t)dt+f(t)+∫[-t,0]f'(t)dt=f(t)

Wherein f(t) is the age of beer and f'(t) is the aging speed.

Q.E.D.


Now try to prove me wrong

"I hate temporal mechanics!" - Miles O'Brien, past and future copies

[frau kaleun]

Originally Posted by TLAM Strike

That is only if they are using Tachyons. As far as I know Tachyons have nothing to do with Quantum Entanglement.

If quantum entanglement is the issue, I suggest a good quantum conditioner. Reduces entanglement considerably and will also help repair any split ends on your string theories.

[DarkFish]

Originally Posted by frau kaleun

[Jimbuna]

Originally Posted by DarkFish

So:

∀t∈ℝ, ∂f∈ℕ, 0 ≤ ∂f ≤ 2: f'(t)=-f'(-t) ⇒ f'(t)+f'(-t)=0 ⇒ ∫[0,t]f'(t)dt+f(t)+∫[-t,0]f'(t)dt=f(t)

Wherein f(t) is the age of beer and f'(t) is the aging speed.

Q.E.D.


Now try to prove me wrong

I've got the bugga drunk before you can convince anyone those details/figures makes sense.