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SUBSIM: The Web's #1 resource for all submarine & naval simulations since 1997 |
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#31 |
Ace of the Deep
![]() Join Date: Dec 2004
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Yes, Irish, they did. Not to hijack the thread, but Camo/deceptive paint jobs also to deceive length overall...especially during WW1. No matter how tall or short a mast, the LOA from a 90˚ perspective works just as well.
edit: viewing a man on deck and allowing for ~2m for his height, one could just as easily compute range. btw: welcome aboard, badwolf! ![]()
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[SIGPIC][/SIGPIC] During times of universal deceit, telling the truth becomes a revolutionary act. ~ George Orwell Last edited by don1reed; 06-17-08 at 01:06 PM. |
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#32 |
XO
![]() Join Date: Jun 2008
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Thankyou don1reed,
A new alias badwolf (aka - The Bad Wolf), but my old computer died, flung it overboard. Couldn't retrieve old data, so as everyone called me badwolf anyway. I took it up. The reason I was interested in the thread was that I'm changing the GUI to suit my own taste and hopefully improvements. Have had trouble associating U-jagd with the inbuilt periscope measurements. The Watch Officer's range to the calculated distance, weren't the same. Having read these posts I can correct this error now. |
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#33 | ||
Pacific Aces Dev Team
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![]() Quote:
Mast in metres (x1000) = Distance in metres Scale heigth reading for the target 25m (x1000) = 500m range 50 and 25m (x1000) = 250m range 100 Thus when a target with a 25 m mast covers 50 units of the scale it is at 200 metres, and when covering 100 units (Which are exactly 6.25 degrees) it is at 250 m i.e. 10 times its heigth. Probably the scope shipped some slide ruler as equipment to go along with it and simplify the calculations. Quote:
@Badwolf: wellcome ![]()
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One day I will return to sea ... |
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#34 |
XO
![]() Join Date: Jun 2008
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Thankyou Hitman
Good to talk to you again. If that's correct then- [late war] 100 units (6.25 deg) = [early war] 10 units (6.25 deg) I thought the divide by 16 was a good argument as it explained why the centre thick lines were positioned that length. 1 to 10 ratio for horizontal line to tip of thick line. Thus giving an instant area prospective for other ranges without measuring. i.e half size = *20 - quarter size = = *40. So good estimation and easy maths gives quick range calculations. Afterthought The horizontal marks look like early war. If we could measure that to the vertical to get a relationship (hard due to angle of picture). But it does look more a 10 to 160 ratio rather than 10 to 100. Additional thought I do think that the /16 does means divide by 16 if not why not use symbol 10/16 or just 0.625. (probably easier to do calculation in late war) I can't understand how 100 units*0.625 deg (10/16) = 6.25 deg should equal 62.5 deg Perhaps running trials is the solution using the officer for conformation. Anyway thankyou Hitman for helping me out. ![]() Last edited by badwolf; 06-17-08 at 05:28 PM. |
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