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031315, 09:05 AM  #796  
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Join Date: Jan 2010
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Quote:
For now I understand how it works, the only doubt is the mathematical formula at the end of the document: .....Because we have done 3 plots after the initial one –we have registered 3 times his advance after the first bearing and range each 3 minutes with a total of 9 minutes, we can say that 3250/3 = 1083, 3333 yards each three minutes. Using the simple formula Speedx100= distance (in yards) travelled in 3 minutes, we know that this means a speed of 10.8 knots (Knock off the last two ciphers and you have the speed)..... ecc ecc..... because the tutorial was made for SH4 and distances are in yards and not in metric (kilometers) as we have in SH3. My only doubt is the final formula can be applied as the same in kilometers? For the rest no problem at all.
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031315, 06:50 PM  #797  
Hellas

Quote:
no you can't use the same formula with km for getting the speed : Speed = 1.944 * ( d / t) where d=distance in meters and t=time in seconds
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031315, 10:15 PM  #798 
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Join Date: Jan 2010
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ahaa yess alles klar now
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031515, 05:09 AM  #799 
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If you are measuring distance in meters just use a time interval of 3:15.

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