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#61 | |
Ocean Warrior
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45 degrees is just a point at which the target's lengt is about 75% of what it would be broadside, but you also get the added advantage that 70% of the target's speed gets added to the closing speed of your torpedo, which is a big help. The 45 degrees works even better if you use a spread from aft to bow, as all the torpedoes arrive at the same time. You can use this method though to attack any angle you want, even from behind. Thanks for saying about that method you use and yes, it's essentially the same procedure you used to use on Sub Battle Simulator (sounds great :-). The only slight difference is, this is slightly simplified. All we need to find is the ratio between the two closing distances. For that, where you are using distance target travelled, versus distance torpedo travelled, we are taking that equation and simplifying it just a bit. We are trying to find the angle formed by the two distances travelled, prior to collision for an unspecified unit of time. Your method of using distance travelled by target and distance travelled by the torpedo is great and will give you the correct answer. We can simplify that a bit though, as speed = distance * time for both target distance travelled and torpedo distance travelled, then we can say that the time component of each equation is the same. So, we can substitute it for a value of one. Thus the ratio between distances travelled becomes the ratio between speeds. That simplifies things a bit, as we don't have to work out how far things have travelled, only how fast ![]() Do you still use this method? If so, does it still serve you well?
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#62 |
Ocean Warrior
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[quote=Munchausen]After thinking about it awhile, I realized this method can be done at any angle, without using the TDC at all ... but (I think) I did it bass-ackwards. Here's what I did, using RR's single mission scenario.
<SNIP Excellent Tutorial> So, was that bass-ackwards or what?[/quote Munchausen, that was a brilliant example. You even measured the angles to the ends for extra accuracy ![]() For those that have asked why use the TDC, the answer is you don't have to at all, but if you do put AoB and the bearing into the TDC and ask it what it thinks, it should say zero gyro angle, if it doesn't then you've done something wrong - probably either drawn with the wrong torpedo speed, or you haven't selected the right torpedo speed in the torpedo panel. It may be useful as a double checking aid. It's a bit trickier to work out the AoB in your head, but it's just 180 - target and torpedo intersection angle - the bearing your drawing gives you. That's based on a bit of maths that says all angles in a triangle add up to 180 degrees, so if you know the intersection angle (angle 1) and the bearing you shoot at (angle 2) then the AoB (angle 3) must be (180 - angle 1) - angle 2. There's only one thing I can add to that Munchausen and that's you could try using the plot navigation course tool to plot your course beyond the target's track. That way you will be able to measure from that, instead of having to draw it. You can use this method for any attack angle and drawing the speeds over the setup the way you have done really does simplify things, with the use of the course plotting tool, excellent addition! Thanks for taking the time to post that Munchausen! Every bit of discussion helps to generate new ideas. Fantsatic.
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#63 |
Ocean Warrior
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OK, I promise to stop spamming now.
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#64 |
Admiral
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One question, should the time be 3 minutes 15 seconds for Imperial? I am getting the wrong speeds. I peeked in mission editor after missing several times. It works but the tanker in the posted single mission keeps turning and the fish go right by him.
Peabody
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#65 | |
Planesman
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If you wanted to count the herd by counting the legs and dividing by 4, you could measure 3 minutes (we'll call that d), multipy that by 20 (to get yards/hour) and divide that by 2000(to get knots). Knots = (d*20)/2000. Of course, if you're a good mathematician, you say "Wait, we can simplify that!" It simplifies to Knots = d/100. I'm not familiar with the metric knot, so I can't show you exactly why 3m15s works. But it's the same principle at work.
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#66 | |
Navy Seal
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![]() With a longitudinal spread, turning into the attack is a very simple way to avoid because the topedoes all take the same track to the target. Later, when we crank up the PK and shoot the stern, MOT, bow divergent spread, the torpedoes run side by side to the target and life isn't so easy for Mr Tanker. A weakness of the John P Cromwell attack is that he's only 45º from the bearing of the torpedo. He's already halfway into the turn to avoid. Electric torpedoes or night/bad weather shots are good here.
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#67 | ||
Navy Seal
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3:15 works for metric because the yard is 36" long, the meter is 39.37". It is longer, so you need a longer time to measure it. 3:00/36 =3:15/39.37.
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#68 |
Admiral
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I'll double check, I may have had it set to metric because of the JP campaign, but I was getting incorrect speeds on the tanker. So it is probably my fault. I just remember on another thread one was 3min one was 3min15sec, I just didn't remember which and I did get the correct speed using 3min15sec.
Thanks for the answer. Peabody
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#69 | |
Silent Hunter
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3 minutes 15 seconds works because 3600 seconds (1 hour) divided by 18.52 (# of times 100 meters go into a nautical mile) is 194.38 seconds. Rounded to an easy measure that is 3min 15sec. |
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#70 | |
Planesman
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[quote=Pisces]
Quote:
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#71 | |
Navy Seal
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![]() So the entire metric system is based on a surveying mistake! Somehow that is very appropriate. Perhaps it's relationship to human error is the most appropriate measurement of all!
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#72 | |
Commodore
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#73 |
Nub
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Hi all i have just started with manual targeting with the excellent Dick O Kane method and i've had some fair success so far and i am keen to try this new one but one thing i've a problem with is getting accurate speed estimates my nav map dividers measure in tenths of nautical miles rather than yards and this throws me a bit is this a setting or a mod that i need to get yards ?
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#74 |
Ocean Warrior
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Hi BlackBob, welcome aboard! The only reason I can think of for having measurements in tenths of a nautical mile, is if the distance is over 10,000 yards (or 5 nautical miles). Up until that distance, the measurements are in 100s of yards, up to 10,000 yards, over 10,000 yards, the measurments are in tenths of nautical miles.
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#75 |
Nub
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Thanks Nisgeis but even if i zoom in the units remain the same i can measure down to 0.1nm i've just realised that i am only patched to 1.3 could that have any bearing (sorry terrible pun)
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