intercept target solutions ? geometrical method ?

[qmuddy2]

do i have to learn that geometrical target intercept solution business ? or can the tdc (or some other way) work out my intercept point ? thanks i'm intercepting the enemy ships by just guessing about where my intercept point is now, working ok , so far, but i think it will make game more playable if i don't have to guess; thanks

[MantiBrutalis]

If I don't want to do that whole geometric calculation, I just guesstimate:

I check the target's heading and speed (slow for 6 knots, medium for 9 knots). I multiply the speed by 2 - the target will do 12 km per hour when travelling at 6 knots, 18 km/h at 9 knots, etc. (In reality it will take the target a tiny bit longer, but at least you will arrive before it does)

And then you guess. I would guess for example I can intercept in 4 hours. I make the target plot for 48 kms (4x12km/h). I plot my course to that point, full ahead, wait for the speed to catch up... and then check the map, as it will tell you when are you going to get there. If I can't make it in 4 hours, I increase the target's distance, if less then 4, I can decrease it.

That's my lazy procedure. But for targets really far away it may be better to learn the geometry thing. It's not that hard and it's the most precise way.

[UKönig]

And when you get into the area where you think the contact might be, dive to take a listen on the hydrophones. Sounds travel farther underwater than the eye can see from the low lying bridge of the U-boat.

Radar may also be useful here, depending on several factors, but when in doubt, dive.

[sublynx]

Mark I Eyeball will do nicely. No need to learn the geometrical stuff if it doesn't feel right.

On the other hand the one time I survived until late 1943 I began to feel sorry I had not paid more attention to navigation techniques. The airplanes and radar kept making convoy shadowing quite an effort. If I had known how to calculate approaches exactly I could have minimized the time I had to be surfaced and I could have minimized the risk of being out of position if the convoy made a zigzag. A botched approach with radar and escort carriers around can force one to spend an extra day near the convoy with its airplanes, while surfaced. I'm now trying to learn the techniques that might help me keep my boat from harm's way, if only for a few hours or a day.

[Pisces]

One thing for sure, the TDC doesn't help you finding the intercept course to the target. Only if you strap yourself to a torpedo and hold your breath for as long as needed.

[Tupolev]

While the TDC basically computes a lead angle intercept, its limited to solving with only 3 speeds: 30kts, 40kts, 44kts. Even if you were able to input a correct AOB (which itself would take solving an equation or navmap plotting) and target speed, the lead angle provided wouldn't be accurate as the U-boat isn't making 30kts+.

There are a few GUI mods out there that provide a simulated attack-disk (can't remember the real name of it) and directions on how to use it to solve for the intercept angle and course. However, I've found it more expedient to just do the drawing on the navmap. YMMV.

T

[MantiBrutalis]

Completely baffled by sENoZ's procedure as well...

[Zosimus]

I watched the video and didn't get it. My U-boat comes with a targeting computer, which has yet to let me down. Why not use it?

Originally Posted by Zosimus

I watched the video and didn't get it. My U-boat comes with a targeting computer, which has yet to let me down. Why not use it?

sorry man am french my english is not perfect, i dont get what you mean ^^

Originally Posted by MantiBrutalis

Completely baffled by sENoZ's procedure as well...

lol ^^ i take that as a compliment so

that the best method ever, dont need to complicate your life with useless calcul.

here what we only need is speed target and speed of torpedo = angle of shoot ^^ + being at a angle of 90 Degres = boom. :P

[Zosimus]

All right. Let's assume that we are firing a 28 knot torpedo at a ship that will be 2800 meters away from our original point of firing at the moment of impact. We also assume that the target will be at exactly 90º AOB at the moment of firing. Thus we have a right triangle with a hypotenuse of 2800.

Now let's say, for the sake of argument, that the lead angle is 20º – what will the target speed be?

Sin(20º) = 0.342 so the ship will have traveled 957.7 meters from the time of firing until the time of impact. Accordingly, the ship is traveling at 9.577 knots.

So your formula is:

Lead angle = torpedo speed - ship speed ?

28 - 9.6 = 18.4 not 20.

What if the ship is traveling more slowly? Let's try 2800 hypotenuse and 400 opposite (28 knots and 4 knots relatively). What's the angle? Well, if your formula is right, it should be 28 - 4 = 24? Not even close. The real angle is around 8.2º
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Sorry. I don't get it.

Originally Posted by Zosimus

All right. Let's assume that we are firing a 28 knot torpedo at a ship that will be 2800 meters away from our original point of firing at the moment of impact. We also assume that the target will be at exactly 90º AOB at the moment of firing. Thus we have a right triangle with a hypotenuse of 2800.

Now let's say, for the sake of argument, that the lead angle is 20º – what will the target speed be?

Sin(20º) = 0.342 so the ship will have traveled 957.7 meters from the time of firing until the time of impact. Accordingly, the ship is traveling at 9.577 knots.

So your formula is:

Lead angle = torpedo speed - ship speed ?

28 - 9.6 = 18.4 not 20.

What if the ship is traveling more slowly? Let's try 2800 hypotenuse and 400 opposite (28 knots and 4 knots relatively). What's the angle? Well, if your formula is right, it should be 28 - 4 = 24? Not even close. The real angle is around 8.2º
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Sorry. I don't get it.

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Now let's say, for the sake of argument, that the lead angle is 20º – what will the target speed be?


angle of 20 ? speed target at 10 with 28 knots torpedo.
as shown in my second video the wich without magui mod.


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So your formula is:

Lead angle = torpedo speed - ship speed ?

no my formula still speed target + speed of torpedo + being at an 90 degres angles, nothing else.

the 90 degres will change if the target course and mine is not at 90 degres for sure. the rest will still the same so speed target and torpedo speed.. = you find shooting angles...


______________


What if the ship is traveling more slowly? Let's try 2800 hypotenuse and 400 opposite (28 knots and 4 knots relatively). What's the angle? Well, if your formula is right, it should be 28 - 4 = 24? Not even close. The real angle is around 8.2º



>>>> sorry my english isnt perfect enough to understand what you say here ^^

you ask me what about low speed target ?

always with an 90 degres angles. for example.

the minimum that i can have at speed target will be 5 knots for a 10 angle shooting always with an 90 degres position ( your uboat )

so i guess a 2,5 knots speed target ^^ will be like 5 angle of shoot...

a 6 knots speed target get a 12 angle of shoot always with 28 knots speed of torpedo.


but i think i explain bad my self.

when i say angle so 90 degres, its about positioning your uboat to about the course target.

and when i mean angle of shoot, i mean look trough obs periscop or attack periscop and wait till the boat came to the good number then shoot your torpedo.


for explain good so.



in that video my u boat is in a 90 degres position about the target course. and the shooting angle what i call shooting angle... anyway look in the periscop i just wait until the boat came at 20 wait a bit more cause i want to shoot a specific part of that boat, then shoot.

but i am at a 90 degres angles.

and so if shooting at 20 like in this video the speed of the target was at this moment 10 knots.

this work only for convoy mutlipe target with same speed, or single target that keep a constant speed.

sorry again my english isnt perfect ill do my best to explain ^^

hope you get it now lol.