A little help with a math problem....

[Taygoo]

Neil one thing...


The formel to the arc line see http://mathworld.wolfram.com/LogarithmicSpiral.html part (6)

And from that formel the arc length measured from the origin

So schould it not be [a*e^(b*THETA)*(1+b^2)^(1/2)]/b-[a*e^(b*ZERO)*(1+b^2)^(1/2)]/b=300 and then we find Theta..

I this case I get theta to 15,129

Because we walk from Theta=0 to theta=arc line 3000 m

[Taygoo]

Originally Posted by Task Force

Ooooah god this thread is hard to understand.

Your modern art I don't understand

[Task Force]

dats what I was aiming for when I made it.:rotfl:

[Taygoo]

Originally Posted by Taygoo

Neil one thing...


The formel to the arc line see http://mathworld.wolfram.com/LogarithmicSpiral.html part (6)

And from that formel the arc length measured from the origin

So schould it not be [a*e^(b*THETA)*(1+b^2)^(1/2)]/b-[a*e^(b*ZERO)*(1+b^2)^(1/2)]/b=3000 and then we find Theta..

I this case I get theta to 15,129

Because we walk from Theta=0 to theta=arc line 3000 m

And if theta=15,129
R=618,278

and 15,128-4pi=2,56263 radian
(180/pi)*2,56263=146,828 degress from x-acres or course 303.172

So if according to this, if I go from the startingpoint(a,0), west(course 270) a meters(29.99803486) I will be (0,0) and now I go course 303,172 and walk 618,278 meters, then I will be at the treasure???

[Onkel Neal]

Originally Posted by Letum

Ahh, but you did it the correct way.

Yeah, I asked some college students

[Letum]

Originally Posted by Neal Stevens

Yeah, I asked some college students

Pfft!
Not asking college students is probably why I did so badly at college.

[Taygoo]

Originally Posted by Letum

Neal, is your daughter sure about the second bit?

I find 3000m to be at ~13.76 radians...(4.38pi).
It may well be me that is wrong tho...I'm very much on the edge of my depth.

How did you figure out that number

Because my calculation is wrong...