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#31 | |
Watch
![]() Join Date: Sep 2008
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Anyway, thank you very much for the response. I That thrust dialog doesn't make it easy to figure out though how much louder it gets per knot- I suppose you have to divide the speed noise into how many knots? Seawolf is base 0, then speed 17 - the seawolves i have set to a flank speed of 40 knots(stock DW is 40, RA puts them at subcommand's 35, i undid that) ..17/40 is .0425... so for every knot, , the noise goes up by .425, eh? Hm, then if i set the Seawolf and Jimmy carter passive sonar level to the Virginia's 53..(or maybe 52)- then all that's left is the 0 -17 speed noise of SW, and 3 - 16 vir Except, as you mentioned 5 years ago, that's 3 +16.(for the Vir) So it's 19, compared to 0 +17 at top speed(SW) So all i need to do is make the passive sonar level 53 , and the SW is quieter off the bat. Or 52.... Thanks for the advice LoBlo ![]() |
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#32 | ||
Subsim Diehard
![]() Join Date: May 2006
Location: Texas!
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Also, I'm not sure if I you mentioned it above or if I missed it, but remember that if you give the SW and the Virginia the exact same Passive Sonar SL and the exact same Speednoise, you are in fact making the SW quieter than the Virginia at any given speed. In your example with the SW given a Passive Sonar SL of 53 and a thrust SpeedNoise of 0 + 17, it grants 0.42 (there's a typo in your above math) increase in noise per knot of increased speed. If the Virgina has a max speed of, hypothetically, 30 knots, then you will need to assign its Speednoise to 12.75 to give the SW and the Virginia equal noise at equal speeds. Quote:
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"Seek not to offend or annoy... only to speak the truth"-a wise man |
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#33 |
Nub
![]() Join Date: Jul 2014
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Sorry for resurrecting an older thread, but I wanted an understanding of how you came up with the thrust value of 12.75 for the virginia to equal the same for the seawolf at its max speed of 30 knots.
Based on what I understand you take your the speed noise per knot found under thrust dialogue and divide it by the max speed of the platform. 17/30 is 0.56 per knot for noise increase. What I want to know is how you reached the conclusion of the 12.75 for the thrust value of the platform to effectively match the seawolf at equal speeds until it passes the max speed of the virginia. I think I got the first part of it I'm just missing how you arrived at the new thrust value from the 17/30 to 0.56 per knot we started with. |
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#34 |
Silent Hunter
![]() Join Date: Dec 2004
Location: AN9771
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Caveat: I never modded DW to test this out.
Afaiu(nderstand) the math, you take the max speed noise (maybe a typo on your part, but it is not "per knot", but total) and divide it by the max speed of the unit to get the speednoise per knot. So for the SW in that example is max speednoise/top speed=17/40 kts= 0.425 noise points per knot. In order for the VA to be equally noisy at equal speed as the SW, the max soundnoise needs to be proportionally lower as the top speed is lower (30 kts). So 0.425x30 kts=12.75 Looking at it in a different way:12.75 speednoise points (VA) is 75% of 17 speednoise points (SW), as is 30 kts (VA) being 75% of 40 kts (SW) Last edited by Pisces; 08-25-14 at 12:14 PM. |
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