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SUBSIM: The Web's #1 resource for all submarine & naval simulations since 1997 |
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Sea Lord
![]() Join Date: Mar 2006
Location: Port Hardy, BC, Canada 75 yo with M.S. & C.O.P.D. & heart problems
Posts: 1,930
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Okay guys, here is the problem. First of all the navmap is 125KM size which 125 km = 54 mm and the time of the day is 1816. I have a convoy 79° from me at a distance of 170 mm on the nav map, they are on a course of 247.5° and travelling at 6 kts. I anticipate they have to travel along that course (247.5°) for a distance of 134 mm on that nav map. What time would it be when they reach that 134 km point?
Next, I plan to intercept them on a bearing of 108°, the distance on the nav map is 45.5mm when they have travelled 134 mm on the nav map. What time would it be when I arrive at my point if I travel at 17 kts. 6 kts/24 hrs = 267 km 17 kts/24 hrs = 756 km Can anyone solve this for me. My brain just cannot comprehend it ![]() ![]() Have I supplied enough information? |
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