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#16 | |
Commander
![]() Join Date: Sep 2004
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![]() Quote:
For example, I spot a medium cargo with a mast height of 23.2m. At 10x magnification I count 5 ticks from the water line to the highest mast and since each mark counts as 20: 5 x 20 = 100. Then with the mast height we have 100 x 23.2 = 2320m Take 2320 and divide by number of tick marks, 5 in this case, and we get 464m but we know the target is about 1700m away. |
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#17 |
Loader
![]() Join Date: Apr 2006
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That can't be the way to do it though. You multiply your 5 marks with 20, but in the end you divide your result with 5 so it really doesn't make any difference if you count 5 marks or 50. In other words, you will always get 464 m as the result for that mast height.
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#18 |
Swabbie
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ok from the horizontal line there are 15 marks total, i line up on a tramp steamer and and count 12 so a total of 240. multiply that by 22.7 and dived that by the 2 remaining marks under that and u get a range of 2724. if u get the aob and speed right and he dosent zig on ya hes going down. there are times when u shouldnt count a mark thats just under the tip of the mast but with practice ull get the hang of it
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#19 |
Swabbie
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Jmr for this to work just as I instructed you have to be on 6X magnification, later ill play with it and see if i can make it work for 10X, but if u try it on 6x im sure that you will be satisfied with the results. But when i get time ill try to see if i can make it work on 10X
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#20 |
Commander
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Ok, I see what I was doing wrong - I wasn't counting from the top and then dividing by the remaining tick marks that are found by counting up from the water line.
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#21 |
Loader
![]() Join Date: Apr 2006
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I don't understand why marks should be counted twice, above and below the mast. This should be a linear formula and all that matters is the apparent height of the mast (in marks) and real mast height.
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