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#1 | |
Grey Wolf
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![]() Quote:
There are times when “close enough” is fine, but unless somebody is told that close enough only applies at close range, they would be led astray. Also easily solvable using vector analysis. Using the fact pattern above, draw a line on the map 30 km long straight up. Draw a line going from the top end of that line but perpendicular, 15 km long. Now draw the third leg of the triangle and measure the angle at the bottom, your lead angle. Allows you to quickly figure out your lead angle for any desired track angle.
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#2 | |
Silent Hunter
![]() Join Date: Dec 2004
Location: AN9771
Posts: 4,904
Downloads: 304
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![]() Quote:
Assume AOB =90 ; Torpedo speed is 30 kts ; Target speed is 15 kts. > Leadangle =30 That means the AOB at firing time should be 60 instead. So align torpedo speed to angle 60: Now lead angle becomes 25.5 degrees for 15kts target speed. That means the AOB at firing time should be 64.5 instead. So align torpedo speed to angle 64.5: Now lead angle becomes 26.75 for 15kts target speed. That means the AOB at firing time should be 63.23 instead. So align torpedospeed to angle 63.25: Now lead angle becomes 26.5 for 15 kts target speed. That means the AOB at firing time should be 63.5 instead. So align torpedo speed to angle 63.5: Now lead angle becomes very close to 26.5 again. No need to continue now. (I did this on my handheld template Attackdisk, reading and disk setting accuracy is getting the better of you beyond this point.)
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#3 |
Grey Wolf
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Oh no I understand that, hence why I said it’s a little more of a laborious process. If it had a tan scale, would be easier. Ultimately the easiest I find if not wanting to use a calculator is vector analysis.
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Ask me anything about the Type VII or IX! One-Stop Targeting Shop: https://drive.google.com/drive/folde...WwBt-1vjW28JbO My YT Channel: https://www.youtube.com/channel/UCIJ...9FXbD3S2kgwdPQ |
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#4 |
Ocean Warrior
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Math, smath
![]() Beats my head exploding anyway. ![]()
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"Realistic" is not always GAME-GOOD." - Wave Skipper ![]() |
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