target speed: the eighty-ten method

[sergei]

Originally Posted by Diopos

greyrider
Ok, if I succeed (say via sonar) to keep a distant target at a relative bearing of 80° while my speed is 2.5 Kts, why am I to suppose a AOB of 10 and a target speed of 14.1 kts and not other solutions (sample on following table)? . . .

OwnShip Speed (kts) ____"Lead Angle" (°) _____AoB (°) _____Target Speed (kts)
__________2.5_________________ 80 __________10 _______________14.2
__________2.5_________________ 80 __________15 ________________9.5
__________2.5 _________________80 __________20 ________________7.2
__________2.5 _________________80 __________25 ________________5.8
__________2.5 _________________80 __________30 ________________4.9

I've quoted this again Greyrider, because this is the question I really want you to answer.

Until I am given a convincing answer to this question, I remain extremely sceptical of the viability of this method except in very specific circumstances.