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Old 10-08-09, 01:11 PM   #1
Letum
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I'm not so sure Steve.

The Sub may displace 1000 tons, but it' weight in the water with tanks
flooded will be far, far less than 1000 tons. At neutral buoyancy the weight
will be zero.
I would be surprised if the basalt tanks could get more than 10 tons extra
weight, but I could certainly be wrong.
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Old 10-08-09, 01:18 PM   #2
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Quote:
Originally Posted by Letum View Post
I'm not so sure Steve.

The Sub may displace 1000 tons, but it' weight in the water with tanks
flooded will be far, far less than 1000 tons. At neutral buoyancy the weight
will be zero.
I would be surprised if the basalt tanks could get more than 10 tons extra
weight, but I could certainly be wrong.
As I understand it a basketball filled with air weighs more on the scale than a deflated one, but I might be misremembering.

In any case, the mass will be the weight of the boat plus the weight of the water on board, so the submerged displacement will indeed be much more than the surfaced displacement.

And if the boat is headed downward at the time of the snagging, you will also have the momentum added into the equation.

All I know for sure is that the Japanese experiment describes a bomb attached to the hook, and that the Allies didn't do it as a matter of course.
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Old 10-08-09, 01:55 PM   #3
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Quote:
Originally Posted by Sailor Steve View Post
In any case, the mass will be the weight of the boat plus the weight of the water on board, so the submerged displacement will indeed be much more than the surfaced displacement..

I think you might be confusing mass and weight.
The mass of the boat is the mass of the boat and the basalt, however
the weight of the boat is the mass of the boat minus the mass of the
water displaced multiplied by the force of gravity (this value is always 1 on
earth so we can ignore it).

When any boat is not sinking or rising it's weight is zero because the
mass of displaced water is equal to the mass of the boat.

When a boat is sinking that means it's mass is greater than the mass of
the water displaced. In a u-boat the weight of the boat can not exceed
the spare capacity of the basalt tanks after they are filled to neutral
buoyancy.

The VIIC can change it's weight by about 135 tonnes (2x 25m^3 tanks,
2x32m^3 tanks and the ~20m^3 tank ) and can change it's displacement by 118 tonnes.

That means that the VIIC will never weigh more than ~16 tonnes in water.
Under normal operation this value would likely be a deal lower than 16 tonnes.

You are quite right to worry about momentum tho.
Momentum is a product of the mass of the two boats and not the weight.

The sun, for example, has almost no weight, but plenty of momentum.
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Old 10-10-09, 12:50 PM   #4
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Quote:
Originally Posted by Letum View Post
I think you might be confusing mass and weight.
Possibly. It wouldn't be the first time.

Quote:
When any boat is not sinking or rising it's weight is zero because the
mass of displaced water is equal to the mass of the boat.
So if a diver came upon the submerged sub, he would be able to push it as if it wasn't there? Or if a fisherman snagged it he could just reel it in? That doesn't sound right to me. The thing still has the same mass, and any attempt to hook it is going to meet with that many tons of resistance.
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Old 10-10-09, 02:58 PM   #5
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I one of the hooks catches some holes of the hull of the sub it would just rip it apart, how it happend in the movie
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Old 10-10-09, 03:02 PM   #6
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Originally Posted by Sailor Steve View Post
So if a diver came upon the submerged sub, he would be able to push it as if it wasn't there? Or if a fisherman snagged it he could just reel it in? That doesn't sound right to me. The thing still has the same mass, and any attempt to hook it is going to meet with that many tons of resistance.
It's not the weight that would stop him, but the momentum and drag that
would make is difficult to move the sub fast. However, the diver would
theoretically be able to get the sub moving with virtually no effort, just very
slowly at first because of the momentum/inertia and then not reach a high
top speed because of the drag.
The weight of the sub would not be an issue as it has no weight in the
water at neutral buoyancy. Inertia and drag would be the big issues.
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Old 10-10-09, 05:10 PM   #7
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Imagine the submarine as a very big paddle. VERY big paddle, now imagine the said diver try and paddle with it.
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Old 10-10-09, 06:40 PM   #8
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I don't they would try to "catch" the sub.

IIRC the japanese would "Hook" a sub and let go of it, buoy attached. that way you can watch exactly where this sub is going, and there was even some oddball way to tether a pole (with buoy) to it and guess within a few feet how deep the sub was.
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Old 10-11-09, 06:51 PM   #9
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I´s better use a giant net with some explosive devices attached to it

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Old 10-08-09, 01:55 PM   #10
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I think using a rather improbable movie like 'Below' as a basis for which ASW devices to include in SH5 would be a detriment to the sim. It's the only sub movie I can think of which rivals U-571 for historical inaccuracies.
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