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#29 |
Ocean Warrior
![]() Join Date: May 2007
Posts: 2,689
Downloads: 34
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Using the reverse side of the tool to solve the speed problem.
Step 1. Adopt an intercept course. Do not change speed or heading until procedure is complete. Step 2. Observe AOB and bearing to target and current own speed. Start chronometer. Say AOB = 35; bearing to target =270, that is 90 on the Peilung wheel. Own speed =4kts. Set AOB to own speed. Look under bearing to target. The speed here is the target speed, assuming no change in relative bearing. You can see that the speed of the target here is 7knts. ![]() Stage 2 If the relative bearing to target changes, then you need to perform a speed correction. Up scope and note new bearing to target. Get range to target. Note exact time elapsed. Down scope. calcualte difference in bearing position. Let's say after 5 mins exactly, the change in bearing = 280-270 = 10 degrees. Range to target is 1500m 1. Set the range in meters opposite the original AOB, that is 1500m opposite 35 on the peilung wheel. 2.Set the time elapsed, 5 mins, on the zeit wheel to match the change in bearing 290-280= 10 degrees. 3. Read off the speed correction across from the red line on the zeit wheel. Here you see it is 3kts If the target advanced relative to you, add this correction to the previous estimate. If you advanced relative to the target, subtract it. In our case we add the speed correction, so 7knts +3knt = 10kts ![]()
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"Enemy submarines are to be called U-Boats. The term submarine is to be reserved for Allied under water vessels. U-Boats are those dastardly villains who sink our ships, while submarines are those gallant and noble craft which sink theirs." Winston Churchill |
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