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SUBSIM: The Web's #1 resource for all submarine & naval simulations since 1997 |
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#9 | |
Seasoned Skipper
![]() Join Date: Mar 2008
Posts: 698
Downloads: 262
Uploads: 0
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![]() Quote:
![]() ![]() Lead Angle = asin (V sin A / (V ^ 2 + T ^ 2 - 2VT cos A) ^ 1/2) V= Target speed T= Torpedo Speed A= Track angle/Intercept angle. The program automatically recognizes my variables and asks for input. When I input the following values for each as a test... V(Target speed) = 9 T (Torp speed) = 30 A (Intercept angle) = 75 ...it spits out (= -0.11) I take this to mean an 11 degree lead angle. Is that how I should be doing this? I tried it with a different lead angle variable again to be sure. V(Target speed) = 9 T (Torp speed) = 30 A (Intercept angle) = 135 and it spit out (=0.02). or a 2 degree lead angle That doesn't seem right to me. Can anyone see what I've done wrong here? Is my formula off? Do I need to make the calculator see my output "Lead Angle" as an angle and not a straight number value or something? Pisces, thanks again for the trig refresher. While I love playing this game, this has reminded me why I was a "social science" person.
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Tags |
torpedo, trigonometry, zero gyro |
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