Question about GWX Torpedoes and Carnovaro's Charts

[TorpX]

Originally Posted by P_Funk

Anybody have an explanation of how to figure the math out on this? I could probably stare at a blank piece of paper and burn through a dozen pencils over the course of 4 or 5 hours and figure it out but maybe someone can save me the trouble.

For a perpendicular track:

Tangent of lead angle = target speed / torpedo speed

or

lead angle = Arctangent (target speed / torpedo speed)

So, for example, firing a 28 knot torp to hit a ship traveling at 10 knots requires a lead angle of 19.6 degrees.

Just remember, this only works for a 90 deg. track.