Quick question on speed calculation

[Sag75]

Originally Posted by Fader_Berg

To clearify the AOB problem a little more...

If we would look at a moving target in an AOB of 90 degrees. It would cross our field of view as fast as possible in any given speed. While if we watch it in a AOB of 45 degrees it would appear to cross it slower, or actually (sin(45) =) 0,71 as fast over the same view. But, at a fixed aim point, and as the AOB of 45 degrees also makes the ships footprint only (sin(45) =) 0,71 of its true (90 degree) size. The two factors evens out.

So a ship with an AOB of 45 degrees will appear to move 0,71 slower across our point of aim than a ship with a AOB of 90 degree. But the 0,71 smaller footprint of the 45 degree target compensates for that, and the time for both to travel their full body will be the same.

Thanks! this is the confirmation I was looking for!