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#1 |
Commodore
![]() Join Date: Sep 2002
Location: Way out there
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Hey fellas,
whats the equation for intercepting a convoy. Lets say you get a radio report of a convoy that's about 100km away, travelling at 7kts, course 030. You are travelling 000 at 18 kts and the convoy is bearing 315 from your position. what calculation do you need to perform to intercept the convoy? Mostly I estimate it visually with good results, but sometimes I believe that the target got by. Thanks for the formula, and I hope this isnt too much of a bonehead question ![]() edit: I guess its a physics equation and here are the values you know: 1. target course: 030 2. target speed: 7kts 3. target distance: 100km 4. own course: 000 5. own speed : 18kts 6. target bearing: 315 also, I think you need to change the knots to meters per second, which I dont know how to do. any help appreciated! |
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#2 |
Soundman
![]() Join Date: Jan 2008
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http://www.subsim.com/radioroom/showthread.php?t=88961
This gives you a plan ![]() http://www.subsim.com/radioroom/showthread.php?t=96026 Some other helpful stuff ![]() |
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#3 |
Commodore
![]() Join Date: Feb 2005
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__________________
My Father's ship, HMCS Waskesiu (K330), sank U257 on 02/24/1944 ![]() running SHIII-1.4 with GWX2.1 and SHIV-1.5 with TMO/RSRDC/PE3.3 under MS Vista Home Premium 32-bit SP1 ACER AMD Athlon 64x2 4800+, 4GB DDR2 RAM, 400GB SATA HD Antec TruePower Trio 650watt PSU BFG GeForce 8800GT/OC 512MB VRAM, Samsung 216BW widescreen (1680x1050) LCD |
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#4 |
Commodore
![]() Join Date: Sep 2002
Location: Way out there
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Thanks!
that's it! ![]() |
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#5 |
Grey Wolf
![]() Join Date: May 2006
Location: BA8758, or FN33eh for my fellow hams.
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Might I also suggest using a whiz-wheel or slide rule, for that authentic juiced-in U-boat flavor.
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The U-Boat Commander of Love |
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#6 |
Forum Captain
![]() Join Date: Apr 2007
Location: Buenos Aires
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MoBo is by far the best answer to your question
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(Yo no fui ) My DW pics :https://goo.gl/photos/5gBN7WFntLBSAsc17 My SSM2007 pics :https://goo.gl/photos/1Fa6GaEom28AZuc57 |
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#7 |
Silent Hunter
![]() Join Date: Dec 2004
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Intercepting is as 'simple' as the following formula:
lead_angle = arcsine( speed_target*sin(AOB) / speed_uboot ) lead_angle is the angle between the line target_to_uboot and your new course to follow. AOB (Angle on the (target) Bow) is the angle between target's course and the line target_to_uboot. Because your course is due north, the angle between the target bearing (315) and his course (30) is 75deg, so the AOB is the left-over part to 180, which is 105deg. So, first you multiply target speed by sin(AOB) (7*0.966=6.761; if this is above your max speed forget about intercepting him! you won't make it!), then divide by your speed (=6.761/18=0.376). If the result is over 1 you made a mistake somewhere (or you are too slow). If not, you have done it correctly sofar, and you do the arcsin function on it to get the lead_angle (arcsin 0.376= 22 deg). Now your new course is: 0(current course) + 315 (relative bearing) + 22deg (intercept angle)= 327 deg Range: Range has no influence on the course to take, only on the time it takes to get there. First draw the triangle on the map based on target course, the line to the target, and your new intercept course. Then measure from that the distance along the intercept course you follow. If you divide the intercept range (in km) by 1.852 km you get it in nautical miles. Then divide that nautical-mile distance by your speed and get the amount of hours it takes. No need to mess with meter per seconds. Those meter/second calculations are going to take longer than the 3h14min of your intercept. ![]() Also, your max (flank) speed may not be a good idea if you want to safe fuel. Flank speed creates extra holes in you fueltank. ![]() But I myself do like the (circular) slideruler method 1st and foremost, then map drawing 2nd, last but not least digital calculator. My 'least' is (gu)estimating. Last edited by Pisces; 02-08-08 at 12:41 PM. |
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