Why we NEED torpedo failures....

derstosstrupp · 06-02-20, 04:07 AM

This tactic is fun but seriously - can we please have some steering or depthkeeping errors to make something like this not so viable?

stellaferox · 06-13-20, 05:05 PM

Now THIS is an interesting math problem. Can we figure out which bearing-angle we have to take on a ship so that when at a certain speed (say full speed), the bearing on the ship won't change. And can we calculate the ships speed from that?

I tried it but my trigonometry is a bit rusty.... Known parameters are the AOB, own speed and bearing- angle. The best I can do is: Target speed = sin(angle difference from 0 at which bearing keeps constant) x Speed ownship. In other words: the angle difference from 0 is ARCSIN(Target speed/ Own speed)

derstosstrupp · 06-13-20, 05:31 PM

Quote:

Originally Posted by stellaferox

Now THIS is an interesting math problem. Can we figure out which bearing-angle we have to take on a ship so that when at a certain speed (say full speed), the bearing on the ship won't change. And can we calculate the ships speed from that?

I tried it but my trigonometry is a bit rusty.... Known parameters are the AOB, own speed and bearing- angle. The best I can do is: Target speed = sin(angle difference from 0 at which bearing keeps constant) x Speed ownship

You bet!

Target speed = ownspeed x sin (constant bearing) / sin (AOB)

stellaferox · 06-13-20, 05:40 PM

Thank you! The division by Sin (AOB) is essential as I figured out the problem at a 90 deg angle

Could it be that in your video at 44:56 you mention that the constant bearing is 25.2 when it actually is 24.8?

06-02-20, 04:07 AM	#1
derstosstrupp Grey Wolf Join Date: Aug 2008 Posts: 914 Downloads: 490 Uploads: 0	Why we NEED torpedo failures.... This tactic is fun but seriously - can we please have some steering or depthkeeping errors to make something like this not so viable? __________________ Ask me anything about the Type VII or IX! One-Stop Targeting Shop: https://drive.google.com/drive/folde...WwBt-1vjW28JbO My YT Channel: https://www.youtube.com/channel/UCIJ...9FXbD3S2kgwdPQ

06-13-20, 05:05 PM	#2
stellaferox Soundman Join Date: Nov 2007 Posts: 142 Downloads: 51 Uploads: 0	Now THIS is an interesting math problem. Can we figure out which bearing-angle we have to take on a ship so that when at a certain speed (say full speed), the bearing on the ship won't change. And can we calculate the ships speed from that? I tried it but my trigonometry is a bit rusty.... Known parameters are the AOB, own speed and bearing- angle. The best I can do is: Target speed = sin(angle difference from 0 at which bearing keeps constant) x Speed ownship. In other words: the angle difference from 0 is ARCSIN(Target speed/ Own speed) Last edited by stellaferox; 06-13-20 at 05:30 PM.

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06-13-20, 05:40 PM	#4
stellaferox Soundman Join Date: Nov 2007 Posts: 142 Downloads: 51 Uploads: 0	Thank you! The division by Sin (AOB) is essential as I figured out the problem at a 90 deg angle Could it be that in your video at 44:56 you mention that the constant bearing is 25.2 when it actually is 24.8?