Someone do the math for me....

Deathblow · 12-29-05, 04:49 PM

okiedokie.

So I'm shooting at a 30 knot target with a 55kt torpedo with 27nm range (basically a Mk48)...

... what is the maximum launch range that will garantee my torp will not be outrun by the target? 12nm? 15nm? :hmm:

Anyone that can crutch the numbers for me? A formula that can be used to determine the launch range versus the torp speed and range would be great...

Zerogreat · 12-29-05, 05:07 PM

edited
I've got error somewhere...rethinking

I never liked math actuallyÂ¨

MaHuJa · 12-29-05, 05:11 PM

Basically, if you shoot from point blank, you won't have to think about that - unless your torpedo is slower than the target. (40 knot fastest chinese ASW torp vs 40 knot seawolf... As it was without lwami.)

Not that you really want to...

TLAM Strike · 12-29-05, 05:18 PM

About 12 miles. Good rule of thumb, if the target is greater than half your torpedoes range it can out run it if its a warship.

Bill Nichols · 12-29-05, 05:35 PM

Quote:

Originally Posted by Deathblow

okiedokie.

So I'm shooting at a 30 knot target with a 55kt torpedo with 27nm range (basically a Mk48)...

... what is the maximum launch range that will garantee my torp will not be outrun by the target? 12nm? 15nm? :hmm:

Anyone that can crutch the numbers for me? A formula that can be used to determine the launch range versus the torp speed and range would be great...

A 55 kt torpedo covers 27 nm in about 30 minutes.
A 30 kt target can go 15 nm in the same amount of time.
Thus, if the target is more than 12 nm away at time of torpedo launch, then it can conceivably escape (12 nm = 27 nm - 15 nm).

"No escape range" = Torpedo max range - (Torpedo max range / Torpedo speed) * Target max speed

Zerogreat · 12-29-05, 05:44 PM

Hahha, took me half an hour :rotfl:

Max firing range = Torp range * ( 1 - ( Target speed / Torpedo speed)) :P

Deathblow · 12-29-05, 05:53 PM

Sweet! Thanks Bill and Zero.

*bookmarks thread*

Kapitan · 12-30-05, 04:18 AM

ever heard the six minuet rule ?

spped of object x 200 and then u get the range in yard do that a couple of timss as i do and you get there a slower methord but not been far wrong yet.

Fish · 12-30-05, 03:05 PM

. SIX MINUTE RULE

The â€œSix Minute Ruleâ€œ is a rule boat drivers live by. Take the speed of anything in knots, multiply it by 2...then add two zeroâ€˜s at the end of it. This is the distance in yards the object will travel in six minutes.
DISTANCE (yards) travelled in 6 minutes = SPEED(knots) Ã— 200
For a weapon travelling at 55 knots, 55x2 is 110, and putting two zeros at the end of it, is 11,000 yards. That is how far the weapon will travel in six minutes. The range to hear a torpedo ram fire is on the order of 8-12 kyards. So if you fire and are heard counter fire will eat you in roughly six to eight minutes. Now then suppose you fire and evade at 5 knots, a nice, silent speed popular with the Sea Wolves. 5x2=10 and with the two zeros, is 1,000 yards. The active acquisition cone of an TORPEDO is 5,000 yards in diameter. In other words, you are dead against that weapon.
If you shoot, shoot and scoot. Fire on a lag LOS (LOS =3D Line Of Sight, explained in detail a bit later) and then expect counter fire in roughly seven minutes. You have to be at least 2,500 yards away (half an acquisition cone) before that time or you will be acquired. 2,500 yards, working it backwards is 12.5 knots (call it 13) for six minutes. That is the speed at right angles to the firing LOS you have to use to ensure you are not snapped up. It works and works very well. By the time they can TMA your speed and range, you are out of the cone.

From the THE BLUE BOOK OF SUBMARINE OPERATIONS, by Admiral R.Blue and Vice Admiral Homer

12-29-05, 04:49 PM	#1
Deathblow Captain Join Date: Sep 2005 Posts: 518 Downloads: 0 Uploads: 0	Someone do the math for me.... okiedokie. So I'm shooting at a 30 knot target with a 55kt torpedo with 27nm range (basically a Mk48)... ... what is the maximum launch range that will garantee my torp will not be outrun by the target? 12nm? 15nm? :hmm: Anyone that can crutch the numbers for me? A formula that can be used to determine the launch range versus the torp speed and range would be great...

12-29-05, 05:11 PM	#3
MaHuJa Sonar Guy Join Date: Jan 2002 Location: 59.96156N 11.02255E Posts: 385 Downloads: 3 Uploads: 0	Basically, if you shoot from point blank, you won't have to think about that - unless your torpedo is slower than the target. (40 knot fastest chinese ASW torp vs 40 knot seawolf... As it was without lwami.) Not that you really want to... __________________ Teaching DW newbies how to climb the food chain.

12-29-05, 05:18 PM	#4
TLAM Strike Navy Seal Join Date: Apr 2002 Location: Rochester, New York Posts: 8,633 Downloads: 29 Uploads: 6	About 12 miles. Good rule of thumb, if the target is greater than half your torpedoes range it can out run it if its a warship. __________________

12-30-05, 04:18 AM	#8
Kapitan Sub Test Pilot Join Date: Mar 2005 Location: UK + Canada Posts: 7,130 Downloads: 77 Uploads: 7	ever heard the six minuet rule ? spped of object x 200 and then u get the range in yard do that a couple of timss as i do and you get there a slower methord but not been far wrong yet. __________________ DONT FORGET if you like a post to nominate it by using the blue diamond Find out about Museum Ships here: https://www.museumships.us/ Flickr for all my pictures: https://www.flickr.com/photos/131313936@N03/ Navy general board articles: https://www.navygeneralboard.com/author/aegis/

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12-29-05, 05:07 PM	#2
Zerogreat Electrician's Mate Join Date: Aug 2003 Location: Czech Republic, Prague, coordinates are sumthin like 50,10 North 14,25 East, not much accurate Posts: 132 Downloads: 0 Uploads: 0	edited I've got error somewhere...rethinking I never liked math actuallyÂ¨

12-29-05, 05:44 PM	#6
Zerogreat Electrician's Mate Join Date: Aug 2003 Location: Czech Republic, Prague, coordinates are sumthin like 50,10 North 14,25 East, not much accurate Posts: 132 Downloads: 0 Uploads: 0	Hahha, took me half an hour :rotfl: Max firing range = Torp range * ( 1 - ( Target speed / Torpedo speed)) :P

12-29-05, 05:53 PM	#7
Deathblow Captain Join Date: Sep 2005 Posts: 518 Downloads: 0 Uploads: 0	Sweet! Thanks Bill and Zero. bookmarks thread

12-30-05, 03:05 PM	#9
Fish Eternal Patrol Join Date: Sep 2001 Location: Netherlands Posts: 1,923 Downloads: 0 Uploads: 0	. SIX MINUTE RULE The â€œSix Minute Ruleâ€œ is a rule boat drivers live by. Take the speed of anything in knots, multiply it by 2...then add two zeroâ€˜s at the end of it. This is the distance in yards the object will travel in six minutes. DISTANCE (yards) travelled in 6 minutes = SPEED(knots) Ã— 200 For a weapon travelling at 55 knots, 55x2 is 110, and putting two zeros at the end of it, is 11,000 yards. That is how far the weapon will travel in six minutes. The range to hear a torpedo ram fire is on the order of 8-12 kyards. So if you fire and are heard counter fire will eat you in roughly six to eight minutes. Now then suppose you fire and evade at 5 knots, a nice, silent speed popular with the Sea Wolves. 5x2=10 and with the two zeros, is 1,000 yards. The active acquisition cone of an TORPEDO is 5,000 yards in diameter. In other words, you are dead against that weapon. If you shoot, shoot and scoot. Fire on a lag LOS (LOS =3D Line Of Sight, explained in detail a bit later) and then expect counter fire in roughly seven minutes. You have to be at least 2,500 yards away (half an acquisition cone) before that time or you will be acquired. 2,500 yards, working it backwards is 12.5 knots (call it 13) for six minutes. That is the speed at right angles to the firing LOS you have to use to ensure you are not snapped up. It works and works very well. By the time they can TMA your speed and range, you are out of the cone. From the THE BLUE BOOK OF SUBMARINE OPERATIONS, by Admiral R.Blue and Vice Admiral Homer