![]() |
SUBSIM: The Web's #1 resource for all submarine & naval simulations since 1997 |
![]() |
#1 |
Girt by Sea
|
![]()
Ok, no giggling about the thread title...
I wanted to set up a mission where there is an equal one chance in three for an option or mission orders to occur. I know, for an equal 1 in 4 chance, I: * place 2 sailboats at 50% probability somewhere on the map * then set up the mission triggers so that: * Sailboat 1 exists (and no Sailboat 2 exists) = 1st mission * Sailboat 2 exists (and no Sailboat 1 exists) = 2nd mission * Both Sailboats exist = 3rd mission * No Sailboats exist = 4th Mission ...but for equal 1 in 3 chance of a mission, is it: * place three Sailboats at 50% somewhere on the map * If Sailboat 1 exists (and no Sailboat 3) = Mission 1 * If Sailboat 2 exists (and no Sailboat 3) = Mission 2 * If Sailboat 1 OR 2 exists AND Sailboat 3 exists = Mission 3 Mathematically, does that work out to an equal one chance in three of the mission occurring? Thanks guys - Math isn't my strong suit - so I wanted to ask ![]() Stew |
![]() |
![]() |
Thread Tools | Search this Thread |
Display Modes | |
|
|