View Single Post
Old 04-10-10, 09:08 AM   #15
karamazovnew
The Old Man
 
Join Date: Mar 2009
Location: Bucharest, Romania
Posts: 1,403
Downloads: 151
Uploads: 0


Default

Quote:
Originally Posted by Aufklarer View Post
Too many people are getting hung up about this.. I understand that the gyro angle set to 0 will show the lead angle required, but when DoK devised this method he didnt have the advantage of 'linked periscope to gyro' that Gutted mentioned earlier. DoK couldnt have accurately known where to move his periscope to achieve the perfect 000 on his gyroscope because his submarine didnt have the facility that the german UBoats did.

While i know that it isnt the most precise solution it is still a historically proven method that was used and that is what i tried to demonstrate. The tutorial is meant to show the DoK attack method, and this is what it does. Variations of angle speed and such are not part of his original method of attack, advances in submarine optics and TDC made the job ever more easier allowing for the variations pointed out previously.

I thank everyone for their comments, but i would like to hear about points people have relating to the DoK attack method specifically.
For a 000 gyroangle shot, it takes 5 minutes of elementary geometry to figure out a formula and print out a few tables with all AOBS and Speeds possible. Actually here's the formula:

Vs-speed of ship
Vt- speed of torpedo
B- 000 gyro bearing
AOB- angle on bow of target at bearing B (at the moment of fire)
this is actually AOB=(Intercept_angle - B)

From the law of sines:

Vs/sin(B)=Vt/sin(AOB)

and after 2-3 minutes you end up with (i might've done something wrong, I was writing in notepad after all):
B=atan[(Vs * sin I)/(Vt + Vs * cos I)]
And there you go, ready for excel (or angle charts if you were using Norie's tables)

Quick checkup: I=90 degrees
B=atan(Vs/Vt)....


Using this in Excel you get:

torp____ship__Bearing for 000 gyro
40_____1_____1.432096184
40_____2_____2.862405226
40_____3_____4.289153329
40_____4_____5.710593137
40_____5_____7.125016349
40_____6_____8.53076561
40_____7_____9.926245507
40_____8_____11.30993247
40_____9_____12.68038349
40_____10____14.03624347
40_____11____15.37625125
40_____12____16.69924423
40_____13____18.00416161
40_____14____19.29004622
40_____15____20.55604522
40_____16____21.80140949
40_____17____23.02549201
40_____18____24.22774532
40_____19____25.40771811
40_____20____26.56505118

Now, O'Kane might not have had his periscope linked to the German TDC (would've been funny). But if a math noob like me can do this in 5 minutes with highschool geometry, i'm sure he could too.
karamazovnew is offline   Reply With Quote