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Old 06-02-20, 04:07 AM   #1
derstosstrupp
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Default Why we NEED torpedo failures....

This tactic is fun but seriously - can we please have some steering or depthkeeping errors to make something like this not so viable?

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Old 06-13-20, 05:05 PM   #2
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Now THIS is an interesting math problem. Can we figure out which bearing-angle we have to take on a ship so that when at a certain speed (say full speed), the bearing on the ship won't change. And can we calculate the ships speed from that?

I tried it but my trigonometry is a bit rusty.... Known parameters are the AOB, own speed and bearing- angle. The best I can do is: Target speed = sin(angle difference from 0 at which bearing keeps constant) x Speed ownship. In other words: the angle difference from 0 is ARCSIN(Target speed/ Own speed)

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Old 06-13-20, 05:31 PM   #3
derstosstrupp
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Quote:
Originally Posted by stellaferox View Post
Now THIS is an interesting math problem. Can we figure out which bearing-angle we have to take on a ship so that when at a certain speed (say full speed), the bearing on the ship won't change. And can we calculate the ships speed from that?

I tried it but my trigonometry is a bit rusty.... Known parameters are the AOB, own speed and bearing- angle. The best I can do is: Target speed = sin(angle difference from 0 at which bearing keeps constant) x Speed ownship
You bet!

Target speed = ownspeed x sin (constant bearing) / sin (AOB)
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Old 06-13-20, 05:40 PM   #4
stellaferox
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Thank you! The division by Sin (AOB) is essential as I figured out the problem at a 90 deg angle

Could it be that in your video at 44:56 you mention that the constant bearing is 25.2 when it actually is 24.8?
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