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06022020, 04:07 AM  #1 
Officer

Why we NEED torpedo failures....
This tactic is fun but seriously  can we please have some steering or depthkeeping errors to make something like this not so viable?
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06132020, 05:05 PM  #2 
Soundman
Join Date: Nov 2007
Posts: 141
Downloads: 51
Uploads: 0

Now THIS is an interesting math problem. Can we figure out which bearingangle we have to take on a ship so that when at a certain speed (say full speed), the bearing on the ship won't change. And can we calculate the ships speed from that?
I tried it but my trigonometry is a bit rusty.... Known parameters are the AOB, own speed and bearing angle. The best I can do is: Target speed = sin(angle difference from 0 at which bearing keeps constant) x Speed ownship. In other words: the angle difference from 0 is ARCSIN(Target speed/ Own speed) Last edited by stellaferox; 06132020 at 05:30 PM. 
06132020, 05:31 PM  #3  
Officer

Quote:
Target speed = ownspeed x sin (constant bearing) / sin (AOB)
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06132020, 05:40 PM  #4 
Soundman
Join Date: Nov 2007
Posts: 141
Downloads: 51
Uploads: 0

Thank you! The division by Sin (AOB) is essential as I figured out the problem at a 90 deg angle
Could it be that in your video at 44:56 you mention that the constant bearing is 25.2 when it actually is 24.8? 
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