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#1 | |
Ace of the Deep
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#2 |
Navy Seal
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For a vibration in the string, the speed depends on the mass and tension on the string (it's a transverse wave). It will be less than c.
For a pull, the string will stretch, and then the wave propagates like sound (longitudinal wave) and will move at the speed of sound in the media. BTW, doesn't matter if you replace the string with a neutronium rod. Still takes time (more than light) to propagate. |
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#3 | |
Admiral
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#4 |
Lucky Sailor
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But thats not the point, the hypothetical string has no stretch and is completely static. A stick with infinite length, no stretch, and no flex, the moment one end is moved, the other moves too.
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#5 | |
Ace of the Deep
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Or to put simple, in the end, light always wins! ![]() Until the next theory is discovered ... ![]() ,
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#6 | ||
Lucky Sailor
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#7 | |
Ace of the Deep
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#8 |
Fleet Admiral
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I may be wrong, but the string in the OP exists at both points a and b at the same time. Depending on the relativity of the observer, the light will either arrive before, after or at exactly the same time as the string movement is felt. It's all relative.
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#9 | |
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#10 |
Navy Seal
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Actually you are right. As I understand it Tachyons travel back in time as they travel faster than c.
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#11 | |
Ace of the Deep
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#12 |
Ocean Warrior
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It should be noted that tachyons themselves are highly speculative, theorized particles.
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#13 |
Navy Seal
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Of course, but I think the point was that relativity doesn't actually forbid something from going over the speed of light, you just can't accelerate anything to the speed of light in the first place.
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#14 |
Ocean Warrior
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That's true for anything with information or mass. However, we can routinely violate c regarding massless particles and radiation.
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#15 |
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Ordinary massless particles can routinly go faster than light in a vacuum?
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