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Originally Posted by Canovaro
Quote:
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Originally Posted by gordonmull
Lots of interesting stuff there, thanks!
I was looking at the u-boat commanders handbook in there and came to this
"The following rule of thumb serves to determine, in good time, the distance of the submarine
When about launch the attack, (torpedo) abreast of the enemy.
In position 5°, the lateral distance from the enemy = 1/10, in position 10° = 1/5, in position
15° = 1/4, in position 20° = 1/3, in position 30° = 1/2 of the momentary distance."
Does anyone have any idea what this means?? |
I don't understand what that means either 
Maybe: when you are in a 90 degrees angle, and you see the target at 10 or 350 degrees, then the distance between the 'crosspoint' and you compared to the distance between the 'crosspoint' and the target is 1/5
That should mean that if he is at 45 degrees the distance sould be 1/1 (both equally far away from the 'crosspoint') |
I think you are almost right. The angles mentioned appear to be AOB. Then, if you take the sine of them the ratios come out close (well, with a large margin of error for the smaller angles) to represent the ratio between your distance to the 'crosspoint' and distance of the target to you. Your 1/1 ratio at 45 degrees would not be correct. 7/10 would be better.