If I got the maths right (6.25 x 1,6 = 10), reducing the field of view from 32 to 20 (20 x 1,6 = 32) would give us the desired result, i.e. the 6.25 º position would jump to the current 10º mark, and we would be getting tenths of 6.25, like in the real historic scope :hmm:
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One day I will return to sea ...
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