Quote:
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Originally Posted by lesrae
Substitute in the values and then do the sum:
x2y – 3x – y when x = -1 and y = 1
= (-1 * 2 * 1) - (3*-1) -1
= -2 - (-3) -1
= -2 + 3 -1
= 0
(I think)
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Strange, by convention numerical factors are always written before the variables so x2y should really be written 2xy.
Otherwise it could be interpreted as x^2*y.