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stellaferoxx · 12-11-24, 02:38 PM

I think there is an error in the formula which computes d.

It is stated as d = E (in hm) x 3.29 (6000/1820) x sin(w)

But E can be given in meters. The 6000 is really 60, one hour x this change of angle and 1820 should be 1852, which is one nautical mile, to get from meters to knots.

Therefore the formula should be (IMHO)

d = E (in meters) x 60/1852 x sin(w). The differences are very tiny though...

12-11-24, 02:38 PM	#11
stellaferoxx Watch Join Date: Feb 2015 Location: Netherlands Posts: 22 Downloads: 77 Uploads: 0	Error in Formula d I think there is an error in the formula which computes d. It is stated as d = E (in hm) x 3.29 (6000/1820) x sin(w) But E can be given in meters. The 6000 is really 60, one hour x this change of angle and 1820 should be 1852, which is one nautical mile, to get from meters to knots. Therefore the formula should be (IMHO) d = E (in meters) x 60/1852 x sin(w). The differences are very tiny though...