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Old 06-12-19, 07:34 PM   #48
makman94
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Join Date: Jul 2008
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hello Derstosstrupp,
I was looking at these two presentations and i want to ask you something


at this point of first presentation, i think that i am missing it.

Quote:
Originally Posted by derstosstrupp View Post
......
Step 4:
Set up TDC for the shot.
1. With scope pointed at the target (collision bearing you’ve been hopefully maintaining), set AOB in TDC to 90 starboard or port based on the direction of the target’s bow.
How do you know that, at this bearing (collision bearing you’ve been maintaining), the AoB is always 90° ?

Look at the following pic (the spoken AoB at this bearing can be anything else):



how can be ignored the above and consider the AoB to be always at 90° at this bearing? what am i missing here ?



ps: Therefore, for calculate target speed:

target speed = [Own speed / sin(AoB)] x sin(target bearing)



Quote:
Originally Posted by derstosstrupp View Post
.....
Step 4:
With scope pointed at (b2), set AOB in TDC to 90 starboard or port based on the direction of the target’s bow.
....
Same question for the second presentation
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