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Old 08-29-17, 12:12 PM   #10
gumbeauregard
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Join Date: Feb 2008
Location: Houston, Texas
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Quote:
Originally Posted by Rockin Robbins View Post
You STILL don't get it. You also need that completely unspecified perfect 90 degree angle to the target track. Trigonometry ONLY WORKS for a right triangle. Leave that crucial piece of information out and precise target speed and torpedo speed alone won't hit the broad side of Hawaii! Rent a set of eyes if necessary and have Corey Harwell explain the situation to you.

Your inability to understand perfectly illustrates why I pick graphical solutions every time over numerical solutions. Inappropriate use of trigonometry, inappropriate use of apparent precision in carrying out calculations to four decimal places, and the inherent lack of error checking in numerical calculations and charts are just unnecessary. Calculations all have unstated preconditions for their validity. Those are not obvious when you are just working the numbers.

Graphical solutions are self-correcting. Put a starboard AoB in there instead of port and it's immediately obvious that you've made a mistake. That's why the attack map is a crucial step in setting up an attack. Just work the numbers and the error is undetected until the torpedo goes somewhere completely different than where you intended. Even if your calculations and table lookups are correct you can't tell when they are inappropriately applied.

Now defend your position that all you need is target speed and torpedo speed to make a valid solution (I've already snuffed that one), fix your method so it works, or go away.
You do not need a precise 90 degree AOB, which a clear understanding of the firing geometry makes plainly obvious. In fact the ideal torpedo track angle is between 100 and 120 degrees as shown on this convenient Wikipedia chart. (Valid only for 46 knot torpedoes)



A understanding of the math involved allows zero gyro angle shots with ANY target AOB. One need only reduce the 90 AOB bearing by the appropriate amount for the AOB situation.

25% reduction for 60 degrees

50% for 40 degrees

75% for 18 degrees.

I still haven't seen your video demonstration of hitting a 27 knot target at 8000 yards with four consecutive torpedoes.

I can see why you are reluctant to post it. It seems you are prone to errors and reluctant to use any method that requires you to accurately determine precise values under pressure.

PS I think it is hilarious that the method you posted by Gutted and mine are identical and in your haste to be "right" you can't even see that.
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