[QUOTE=BigWalleye;2022126] In either case, the intercept angle is 180-(AoB at intercept). I'm pretty sure Dignan will get the correct result if he uses 180-Track angle in his calculations. And DD's formula is correct for
intercept angle not AoB and not track angle.
QUOTE]
That did it
. When I subtract my angle input from 180 i get 17.4 also. To be clear, the angle I am using in my formula is what DD calls "track angle" in his second diagram, the angle formed by the intersection of my course and the target course. So to make this work we need the angle on "the other side" of that intersection, right? Hence subtracting from 180.
Dorjun, "prefered nomenclature" aside, that seems to be the way to go. "That" being using the angle formed by sub course and target course, subtracted from 180. I appreciate this guide. It's something I've been trying to find for a while.
Thanks BigWalleye and thanks DD, Pisces and TorpX for guiding my torps in the right direction throughout this. I've been "Mozarting" the heck out of this over the past few days (Mozarting is when you get obsessed with finishing a project or solving a problem and block out all other distractions and influences in your life...not good). Now hopefully I can actually play the dang game.
