Quote:
Originally Posted by Pisces
Ok, lets say the initial AOB is 90 degrees port. (target goes from your right to left. And your fastest speed is 16 kts. ( so the initial distance to the track is 59 km in 2 hours)
After 2 hours the contact moved 22 kilometers along it's track.
This makes your distance to the new projected meeting point 63 km. (it's 22 degrees to the left)
But this will take longer: 2 hours 8 minutes.
And so, in that time the target moves 23.7 km.
This again moves the projected meeting point even further to the left (23.6 degrees)
And so your distance to this new meeting point grows slightly to 63.6 km
It would take you now a minute more to reach that.
And so on,
and so on. But let's consider this minute close enough for now
In other situations you might have to do more repeated calculations, as your distance to the projected meeting point creeps further away.
So, how do you consider repeatedly calculating the distance that the target moves in the same time it takes you to do it "the easiest and fastest"?
To each his own method, of course. But I think those words better apply to the graphical method as described. Where no calculation is needed.
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I can see where your coming from in theory but in practice it doesn't work that way. I might make one adjustment to the waypoint that intersects the contacts course once I know how long its going to take me to get there and how far the contact would have travelled in that time (I use a pre-printed table for this), but other than that that's it. I always set the waypoint so I'll get there just before the contact does, about 5-10 Kms. I would say that unless the contact makes a course change between the contact report and the point of intercept it will work 99.9% of the time.
Nemo
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"I'm afraid there is no disguising the fact that King's obsession with the Pacific and the Battle of Washington cost us dear in the Battle of the Atlantic".
Sir John Slessor GCB, DSO, MC, DL
AOC-in-C Coastal Command RAF
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Last edited by Captain Nemo; 09-05-12 at 06:31 AM.
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