SUBSIM Radio Room Forums - View Single Post - Anybody in for a deep math question regarding fire angle?

don1reed · 10-12-05, 12:31 PM

Hello Marcus,

here are two diagrams that may be useful:

The first one shows the Offset Angle of Collision (OAC) 16°, (assuming 40nm torpedo speed and AOB of 90°)

SS=Ship's speed
TS=Torpedo speed

This second one shows the Kriegsmarine's diagram accounting for forward throw of the torpedo and 95meter radius gyro turn of the torpedo; and the paralax of the difference between the scope and the bow tubes.

All the best,

10-12-05, 12:31 PM	#4
don1reed Ace of the Deep Join Date: Dec 2004 Location: Valhalla: Silent Generation Posts: 1,149 Downloads: 910 Uploads: 0	Hello Marcus, here are two diagrams that may be useful: The first one shows the Offset Angle of Collision (OAC) 16°, (assuming 40nm torpedo speed and AOB of 90°) SS=Ship's speed TS=Torpedo speed This second one shows the Kriegsmarine's diagram accounting for forward throw of the torpedo and 95meter radius gyro turn of the torpedo; and the paralax of the difference between the scope and the bow tubes. All the best, __________________ [SIGPIC][/SIGPIC] During times of universal deceit, telling the truth becomes a revolutionary act. ~ George Orwell