My math is a bit rusty but I got this:
Think as the radial of the earth is 20.000km long
I don´t know the exact height of the Arleigh Burke Surface Radar, but from a picture it is more than the third part of the ship´s lenght and less than half, so, 500ft = 150m long. Let´s imagine that is it 70m height.
Think as the ESM mast height is 0m
We can get the exact point where the horizon is by doing the following calculation:
(square triangule)
a2 = b2 + c2
400,002,800= 400,000,000 + c2
c2=2,800
c=52.92km or 26nm
is it right??
The farthest flat point in the ocean that an Arleigh Burke can see is 26nm far. So, it can for sure see a 1m mast at 26nm away, and vice versa.
|