Quote:
Originally Posted by Sag75
thanks for answers, I was looking for the trigonometric formula underneth this method,
for instance this method cannot be applied if I have a 20°-30° AoB ship.. probably because there is a trigonometric factor that we can ignore at AoB 90° (for instance Sen(90)=1)
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It might be strange, and I don't think this is 100% possible, but couldn't you use the fixed line method at any AoB? lets say the ship thats 24 meters long crosses your sights in 8 seconds while at 30 AoB. Couldn't you, in theory, multiply the answer you get from that by a specific number so it turns into it as if it was a 90 degree AoB?