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Taygoo · 06-30-09, 02:28 PM

Neil one thing...

The formel to the arc line

see http://mathworld.wolfram.com/LogarithmicSpiral.html part (6)

And from that formel the arc length measured from the origin

So schould it not be [a*e^(b*THETA)*(1+b^2)^(1/2)]/b-[a*e^(b*ZERO)*(1+b^2)^(1/2)]/b=300 and then we find Theta..

I this case I get theta to 15,129

Because we walk from Theta=0 to theta=arc line 3000 m

06-30-09, 02:28 PM	#31
Taygoo Seaman Join Date: Mar 2009 Location: Denmark - Posts: 34 Downloads: 0 Uploads: 0	Neil one thing... The formel to the arc line see http://mathworld.wolfram.com/LogarithmicSpiral.html part (6) And from that formel the arc length measured from the origin So schould it not be [ae^(bTHETA)(1+b^2)^(1/2)]/b-[ae^(bZERO)(1+b^2)^(1/2)]/b=300 and then we find Theta.. I this case I get theta to 15,129 Because we walk from Theta=0 to theta=arc line 3000 m __________________