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Neil one thing...
The formel to the arc linehttp://mathworld.wolfram.com/images/...l/Inline22.gif see http://mathworld.wolfram.com/LogarithmicSpiral.html part (6) And from that formel the arc length measured from the origin http://mathworld.wolfram.com/images/...l/Inline19.gif So schould it not be [a*e^(b*THETA)*(1+b^2)^(1/2)]/b-[a*e^(b*ZERO)*(1+b^2)^(1/2)]/b=300 and then we find Theta.. I this case I get theta to 15,129 Because we walk from Theta=0 to theta=arc line 3000 m |
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dats what I was aiming for when I made it.:up::rotfl:
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R=618,278 and 15,128-4pi=2,56263 radian (180/pi)*2,56263=146,828 degress from x-acres or course 303.172 So if according to this, if I go from the startingpoint(a,0), west(course 270) a meters(29.99803486) I will be (0,0) and now I go course 303,172 and walk 618,278 meters, then I will be at the treasure??? |
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Pfft! Not asking college students is probably why I did so badly at college. ;) |
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Because my calculation is wrong...:shifty: |
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