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Old 12-15-07, 10:06 AM   #12
klh
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Join Date: Jan 2002
Location: Indiana, USA
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Quote:
Originally Posted by jimmie
YES!! Thank you VERY much! I will try this in the game to digest well!

I think you should include this somewhat "advanced" (?) example in the already well-written tutorial to make it yet better!
By the way Jimmie, either formula will work for convergent or divergent courses. Because the sine function is symmetrical around 90 degrees, we don't really have to subtract the angles from 180. It's just easier for me to visualize, and the attack disc calculator only goes up to 90 degrees.






In other words...
sin (Angle) = sin (180-Angle)


Therefore...
sin (AOB) = sin (180-AOB)
sin (TB) = sin (180-TB)


Target speed = Own speed [ sin (180° - B) / sin (180° - A) ] = Own speed [ sin (B) / sin (A) ]

In the above example:
Target speed = 2 knots [ sin (80) / sin (150) ] = 2 knots [ sin (100) / sin (30) ] = 3.9 knots


Last edited by klh; 12-15-07 at 02:44 PM.
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