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Old 03-13-15, 09:05 AM   #796
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Join Date: Jan 2010
Location: MILANO ITALY
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Quote:
Originally Posted by makman94 View Post
...nope...can't find it , probably i deleted them

do you still haven't figure it out ?
Hi Makman, you are toooo kind,

For now I understand how it works, the only doubt is the mathematical formula at the end of the document:

.....Because we have done 3 plots after the initial one –we have registered 3 times his advance after the first bearing and range- each 3 minutes with a total of 9 minutes, we can say that 3250/3 = 1083, 3333 yards each three minutes.
Using the simple formula Speedx100= distance (in yards) travelled in 3
minutes, we know that this means a speed of 10.8 knots (Knock off the last
two ciphers and you have the speed).....
ecc ecc.....

because the tutorial was made for SH4 and distances are in yards and not in metric (kilometers) as we have in SH3.
My only doubt is the final formula can be applied as the same in kilometers?
For the rest no problem at all.
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